Cracking the Code

GregorArturo · 11-12-2008, 01:23 AM

I came across something inteseting while trying to ratify the concept if you can turn infinties into quantum numbers, specifically divisors of 9. Anyways, its seem that all factors that have a multiple of 3 as a numerator and a non-multiple of 3 as the denominator, then you can multiply the numerator and denomator together to get the quantum number. Just another example of why 3,6,& 9 are so bad @$$ haha. For example:

Fraction Shortcut: 6/5 = 6*5 = 30 = 3+0 = 3
Traditional Way: 6/5 = 1.2 = 1+2 = 3

I tested it with a bunch of numbers and it seems pretty solid as long as the fraction doesn't produce an irrational number. The irrational numbers was what I was trying to define.

However, let's take a look at the multiplication pattern of 7 (factors of 7):

Second number after comma is the quantum number
7*1 = 7,7
7*2 = 14,5
7*3 = 21,3
7*4 = 28,1
7*5 = 35,8
7*6 = 42,6
7*7 = 49,4
7*8 = 56,2
7*9 = 63,9

Now think of this:
3/7=3*7=21=2+1=3.
6/7=6*7=42=4+2=6.

Let's now look at 3.
3*1 = 3,3
3*2 = 6,6
3*3 = 9,9
3*4 = 12,3
3*5 = 15,6
3*6 = 18,9
3*7 = 21,3
3*8 = 24,6
3*9 = 27,9
Now you have nine thirds (aka nine one-thirds) that make up the number 3, or 9/3 (trying to make this sound simple). Apply the table to those nine-thirds, with the same notion of 7 in mind:
1/3=1*3=3
5/3=5*3=15=1+5=6
7/3=7*3=21=1+2=3

So this means we can now solve the quantum number for irrational numbers (aka infinities) as long as it can be written as a fraction! Hell ya!

Also, this made me think of my ultimate math question which I can't deduce with any math: Point nine repeating...
aka .999999999999999999999999999999999999999999999

Now mathematicans will say that equals 9/9 or 1 but think about it; even if it does repeat on forever it's not 1! That's a mind *uck I tell ya.

11-12-2008, 01:23 AM	#10
GregorArturo Avalon Senior Member Join Date: Sep 2008 Location: Southern Maine Posts: 560	Re: Cracking the Code I came across something inteseting while trying to ratify the concept if you can turn infinties into quantum numbers, specifically divisors of 9. Anyways, its seem that all factors that have a multiple of 3 as a numerator and a non-multiple of 3 as the denominator, then you can multiply the numerator and denomator together to get the quantum number. Just another example of why 3,6,& 9 are so bad @$$ haha. For example: Fraction Shortcut: 6/5 = 65 = 30 = 3+0 = 3 Traditional Way: 6/5 = 1.2 = 1+2 = 3 I tested it with a bunch of numbers and it seems pretty solid as long as the fraction doesn't produce an irrational number. The irrational numbers was what I was trying to define. However, let's take a look at the multiplication pattern of 7 (factors of 7): Second number after comma is the quantum number 71 = 7,7 72 = 14,5 73 = 21,3 74 = 28,1 75 = 35,8 76 = 42,6 77 = 49,4 78 = 56,2 79 = 63,9 Now think of this: 3/7=37=21=2+1=3. 6/7=67=42=4+2=6. Let's now look at 3. 31 = 3,3 32 = 6,6 33 = 9,9 34 = 12,3 35 = 15,6 36 = 18,9 37 = 21,3 38 = 24,6 39 = 27,9 Now you have nine thirds (aka nine one-thirds) that make up the number 3, or 9/3 (trying to make this sound simple). Apply the table to those nine-thirds, with the same notion of 7 in mind: 1/3=13=3 5/3=53=15=1+5=6 7/3=73=21=1+2=3 So this means we can now solve the quantum number for irrational numbers (aka infinities) as long as it can be written as a fraction! Hell ya! Also, this made me think of my ultimate math question which I can't deduce with any math: Point nine repeating... aka .999999999999999999999999999999999999999999999 Now mathematicans will say that equals 9/9 or 1 but think about it; even if it does repeat on forever it's not 1! That's a mind *uck I tell ya.